Question

vector opposite to (6i-8j ) whose magnitude is 5 units​

Answer 1

Answer:

                          -3i + 4j

Explanation:

Given vector is (6i-8j)

since in vectors, negative sign shows that vector is opposite to given vector

So for opposite vector , apply negative sign

=> -(6i-8j)

=> -6i + 8j

Now we find the unit vector of given vector by the formula

                           \frac{Vector}{Magnitude of vector}

=>                   \frac{-6i+8j}{\sqrt{-6^{2} + 8^{2} } }

the result will be  \frac{-6}{10} i + \frac{8}{10} j

=>    \frac{-3}{5} i + \frac{4}{5} j

It is a vector of magnitude 1 unit

For 5 units , Multiply the given vector by 5

                          5(\frac{-3}{5} i + \frac{4}{5} j )

The result will be as follow

                    -3i + 4j

Hope this helps you,

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