vector p is (3i + 2j) and vector q is (4i + 5j). What is the magnitude of the vector we will get by cross product (p x q)
Answers
Answer:
7k (7 k-cap)
Explanation:
= p × q
= (3i + 2j) × (4i + 5j)
= 3i(4i + 5j) + 2j(4i + 5j)
= 12(i×i) + 15(I×j) + 8(j×i) + 10(j×j)
= 12(0) + 15(k) + 8(-k) + 10(0)
= 0 + 15k - 8k + 10(0)
= 7k
Based on:
i × i = j × j = k × k = 0
i × j = k ; j × k = i ; k × i = j
j × i = -k ; k × j = -i ; i × k = -j
Answer:
Vector p is (3i + 2j) and vector q is (4i+5j).What is the magnitude of the vector we will get by cross product (p × q).
Hey mate,
First let verify your questions. And next enter to calculations .
In the question given that the vector p is (3i + 2j) and vector q is (4i + 5j).What is the magnitude of the vector we will get by cross product (p×q).
According to the given question,
we should find magnitude of the vector.
So,
Here,
Put the value of p and q in (p×q) vector.
Multiplying the values of p and we get the value of magnitude .
Now,
(Substituting the value of p in q )
= 12 (i × i) + 15 (i × j) +8 (j × i) +10 (j × j)
So,
Finally we got the value of magnitude of the vector. The value is 7k (7k-cap)
This is the perfect answer to this question.