Question

vector P is equal to 6 i + 4 root 2 + 4 root 2 k makes angle with Z axis is

Answer 1

(Vector p).k=(modp)cosx
Modp=sqroot(36+32+32)=10
(4root2)÷10=2root2÷5=cosx
X is cosinverse (2root2)/5

Answer 2

Answer:

angle is cos theetha

cos theetha = a vector / a vector mode i.e. a

= 6 i cap plus 4 root 2 j cap plus 4 root 2 k cap / a vector mode i.e. 10

= 4 root 2 / 10

= 2 root 2 / 5 ( ans)