Vector u has its initial point at (-7, 2) and its terminal point at (11, -5). Vector v has a direction opposite that of vector u, and its magnitude is three times the magnitude of u. What is the component form of vector v?
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Hey
Assuming two position vectors :
![\vec{a} = - 7 \hat{i} + 2 \hat{j} \vec{a} = - 7 \hat{i} + 2 \hat{j}](https://tex.z-dn.net/?f=+%5Cvec%7Ba%7D+%3D++-+7++%5Chat%7Bi%7D+%2B+2+%5Chat%7Bj%7D+)
![\vec{b} = 11 \hat{i} - 5 \hat{j} \vec{b} = 11 \hat{i} - 5 \hat{j}](https://tex.z-dn.net/?f=+%5Cvec%7Bb%7D+%3D++11++%5Chat%7Bi%7D++-+5+%5Chat%7Bj%7D+)
Hence, the resultant vector is =
![\vec{r} = 4 \hat{i} - 3 \hat{j} \vec{r} = 4 \hat{i} - 3 \hat{j}](https://tex.z-dn.net/?f=+%5Cvec%7Br%7D+%3D++4++%5Chat%7Bi%7D++-+3+%5Chat%7Bj%7D+)
And so,
![\vec{s}= - 3 \vec{r} = - 12 \hat{i} + 9 \hat{j} \vec{s}= - 3 \vec{r} = - 12 \hat{i} + 9 \hat{j}](https://tex.z-dn.net/?f=%5Cvec%7Bs%7D%3D++-+3+%5Cvec%7Br%7D+%3D+++-+12++%5Chat%7Bi%7D++%2B+9+%5Chat%7Bj%7D+)
Hence, 's' is the resultant vector ^^"
Assuming two position vectors :
Hence, the resultant vector is =
And so,
Hence, 's' is the resultant vector ^^"
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