Physics, asked by vincy93, 11 months ago

Vector
Which of the following sets of forces acting simultaneously on a particle keep it in equilibrium
D) 3N. 5N, ION 2) 4N, 7N, 12N 3) 2N, 6N, SN 4) 5N, 8N, IN
n ne alone a cirenlar nath of radius 5 m. If he completes half of the circle Find
A​

Answers

Answered by sourasghotekar123
0

Answer:

3) 2N, 6N, 5N

Explanation:

GIVEN:

       The following sets of forces acting simultaneously on a particle keep it in equilibrium.

For a body being acted by 3 powers to be in balance it is important that

1. biggest power < amount of staying two powers and

2. littlest power > mod of deduction of staying two powers.

in choice 1. 5+3=8 which is under 10. first condition abused in second choice 7+4=11 which is under 12, again first condition disregarded

in third choice 6+2=8 which is more noteworthy than 5 and 6-2=4 which is under 5. consequently the two circumstances fulfilled.

The option (3) is correct 2N , 6N, 5N

The project code is #SPJ2

Answered by syed2020ashaels
0

Answer:

In 3rd option sets of forces acting simultaneously on a particle keep it in equilibrium.2N, 6N, 8N

Explanation:

  • A simple mechanical body is said to be in equilibrium if it experiences neither linear acceleration nor angular acceleration; unless it is disturbed by an outside force, it will continue in that condition indefinitely. For a single particle, equilibrium arises if the vector sum of all forces acting upon the particle is zero.
  • In 3rd set we can see that sum of the two forces is equal to the third force hence the body is supposed to be in equillibrium
    6 + 2 = 8N
    #SPJ2
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