Vectors 3a -5b and 2a +b are mutually perpendicular then the cosine of angle between them is
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This can be solved with concept of dot product
acc to ques ,
vector (3a-5b) . (2a+b)=0
|3a-5b|*|2a+b|Cosθ=0
Cosθ=0
θ=90 degrees or π/2 radians
acc to ques ,
vector (3a-5b) . (2a+b)=0
|3a-5b|*|2a+b|Cosθ=0
Cosθ=0
θ=90 degrees or π/2 radians
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