Vectors A and B are given as A = 3i+4j-2k and B = 2i-6j+3k. Evaluate AxB and find the angle between A and B.
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Answer:
24i - 13j + 10k
Explanation: here in the question he is asking the cross product so,
cross product of A and B = i(12+12) - j(9+4) + k(18-8)
= i(24) - j(13) + k(10)
=24i - 13j + 10k
If there any mistake can please correct
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