Vectors have magnitudes 3 unit and 4 unit
respectively. What should be the angle between them if
the magnitude of the resultant is (a) 1 unit, (b) 5 unit
and (c) 7 unit.
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Answer:
|a|−→=3
& ∣∣∣b→∣∣∣=4
(a). If R= 1 unit
then 32+42+2.3.4cos(θ)−−−−−−−−−−−−−−−−−√=1
→25+24cos(θ)=1
→24cosθ=−24
→cosθ=−1
→θ=1800
(b).32+42+2.3.4cosθ−−−−−−−−−−−−−−−−√=7
→25+24cosθ=49
→24cosθ=24
→cosθ=1
→θ=cos−1(1)=0∘
Hence angle between them is
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