Ved travels 600 km to his home partly by train and partly by car . He takes 8 hours if he travels 120 km by train and the rest by car . He takes 20 minutes longer if he travels 200 km by train and rest by car . Find the speed of train and that of the car .
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Given:
- Ved travels 600 km to his home partly by train and partly by car.
- He takes 8 hours if he travels 120 km by train and the rest by car.
- He takes 20 minutes longer if he travels 200 km by train and rest by car.
To find: the speed of the train and that of the car
Solution:
Let the speed of the train be x kmph and that of the car be y kmph
1st condition.
- 120 km by train and (600 - 120) km = 480 km by car
- Then the the train travel was of 120/x hours and the car travel was of 480/y hours.
- Then, 120/x + 480/y = 8
2nd condition.
- 200 km by train and (600 - 200) km = 400 km by car
- Then the train travel was of 200/x hours and the car travel was of 400/y hours
- 20 minutes = 20/60 hours = 1/3 hours
- Total time taken = 8 + 1/3 hours = 25/3 hours
- Then, 200/x + 400/y = 25/3
We have found two equations:
- 120/x + 480/y = 8 ... ...(1)
- 200/x + 400/y = 25/3 or, 8/x + 16/y = 1/3 ... ...(2)
Multiplying (1) by 1 and (2) by 15, we get
- 120/x + 480/y = 8
- 120/x + 240/y = 5
On subtraction, we get
- 240/y = 3
- or, y = 80
Putting y = 80 in (1), we get
- 120/x + 480/80 = 8
- or, 120/x + 6 = 8
- or, 120/x = 2
- or, x = 60
Answer:
- Speed of the train = 60 kmph
- Speed of the car = 80 kmph
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