Question

Vedan
14. The range of the principle value branch of the function
Y=sin inverse x​

Answer 1

Answer:

We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/4) = 1/√2. So, the principal value of sin-1(1/√2) = π/4. We know that the range of the principal value branch of sin-1(x) is (−π/2, π/2) and sin(π/2) = 1.09-Nov-2020