Math, asked by vineetmhp5232, 1 year ago

Veena is 3 years older than her brother Rohit six years ago, Veena's age was four times the age of Rohit find their present ages

Answers

Answered by bhagyashreechowdhury
10

Given:

Veena is 3 years older than her brother Rohit six years ago, Veena's age was four times the age of Rohit

To find:

Their present ages

Solution:

Let's assume "x" years as the present age of Rohit.

So,

Veena's present age = (x + 3) years

6 years ago:

Rohit's age = (x - 6) years

Veena's age = (x + 3) - 6 = (x - 3) years

It is given,

Veena's age 6 years ago = 4 × [Rohit's age 6 years ago]

∴ (x - 3) = 4 × (x - 6)

⇒ x - 3 = 4x - 24

⇒ 4x - x = 24 - 3

⇒ 3x = 21

x = 7 years ← Rohit's present age

Veena's present age = x + 3 = 7 + 3 = 10 years

Thus, the present age of Rohit is 7 years and Veena is 10 years.

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Answered by maqsoomtaqi
0

Step-by-step explanation:

Reena is 3 years olders than her brother Rohit six years ago Reena age was four times than age of ohit find their present agees

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