Math, asked by mallanagoud29, 20 days ago

Veena plans to tile his room floor with square tiles. Each side of the tile is 20 cm. His room is 36 m long and 18 m wide. How many tiles will Veena need? ​

Answers

Answered by aniketaryan960
3

Answer:

Given:

1. Tiles are square (20 cm)

2. Room is rectangle (36m and 18m)

Area of the square tiles is:

= Side × Side

= 20 × 20

= 20²

= 400 cm² or 4m²

Area of his rectangular room is:

= length × breadth

= 36 × 18

= 648m²

Tiles needed:

= Area of the room/Area of the tiles

= 648/4

= 162

∴ 162 tiles are needed

Answered by ObnoxiousS
23

✴️ Concept :-

To solve such questions, we must be acquainted with perimeter and area of 2 - Dimensional shapes. In this question, we have to find out the number of tiles, we need to apply some basic sense into it, as :-

  \qquad \bull \: \red{ \underline{ \boxed {\sf Number \:  of \:  Tiles  =  \dfrac{Area \:  of  \: room}{Area  \: of  \: each  \: tile} }}}

Now, we will simply calculate the area of the room and the area of each tile with the help of some formulas from those given below :-

\begin{gathered}\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}\end{gathered}

{ Kindly view this through web or if you are on app, then you may refer to the attachment }

✴️ Given Information :-

  • Length of the room = 36 m
  • Breadth of the room = 18 m
  • Side of each tile = 20 cm

✴️ Formula Used :-

 \sf \qquad1. \:   \blue{\underline { \boxed{ \sf  Area_{square} = Side  \times Side }}} \qquad \:  \:  \\  \\   \sf\qquad2. \:   \purple{\underline { \boxed { \sf  Area_{rectangle} = Length \times Breadth}   }}

✴️ Solution :-

First of all we will find out the area of the room. We get :-

 \sf :  \longrightarrow Area_{room} = 36 \times 18 \\  \\ \sf :  \longrightarrow Area_{room} =648 \:  {m}^{2}  \:

Now we will calculate the area of the square tiles. We get :-

\sf :  \longrightarrow Area_{tile} =20 \times 20 \: \\  \\ \sf :  \longrightarrow Area_{tile} =400 \:  {cm}^{2}  \\  \\ \sf :  \longrightarrow Area_{tile} =4 \:  {m}^{2}

Now we can calculate the number of the tiles. We get :-

\sf :  \longrightarrow number \: of \:  tiles = \dfrac{648}{4}  \\  \\ \sf :  \longrightarrow number \: of \:  tiles =162 \:

Therefore, the number of tiles needed is 162.

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