Question

Vehicle of mass 1500 kg, moving with a velocity of 30m/s is stopped in 15 seconds on applying breaks. Find the retardation and retarding force.​​

Answer 1

Answer:

• $Retardation = 2m/s^2$

• $Retarding \ force = 3000\:N$

Explanation:

$Given:-$

• Mass = 1500 kg

• Initial velocity = 30 m/s

• Final velocity = 0 m/s

• Time = 15 seconds

$ToFind:-$

• Retardation & retarding force

$Solution :-$

$Acceleration\:=\:\dfrac{v\:-\:u}{t}$

$\implies \:\:Acceleration = \dfrac{0\:-\:30}{15}$

$\implies \:\:Acceleration = \dfrac{-30}{15}$

$\implies \:\:Acceleration =-2\:m/s^2$

$\implies \:\: Retardation = 2m/s^2$

$Force =Mass\times\:Acceleration$

$\implies \:\:Force = 1500 \times -2$

$\implies \:\:Force = -3000 \ N$

$\implies \:\:Retarding\:force=3000\:N$

Answer 2

Given :-

• Mass,m = 1500 kg
• Initial velocity, u = 30 m/s
• Final velocity, v = 0 m/s
• Time taken, t = 15 sec

Need To Find Out :-

• Retardation, a =?
• Retarding force, F =?

Solution :-

We know that :-

$:\implies {\sf Acceleration=\dfrac{Final\: Velocity-Inital\: Velocity}{Time}}$

$:\implies\sf Acc^{n} = \dfrac{0 - 30}{15}$

$:\implies\sf Acc^{n} = \dfrac{ - 30}{15}$

$\pink{:\implies\underline{\boxed{\sf Acc^{n} = -2m/s² }}}$

(Since, Negative acceleration is retardation )

$\therefore\:\underline{\textsf{Retardation is \textbf{2 \:m/s²}}}.$

$:\implies \sf Retardation \: Force = Mass \times Retardation\:$

$:\implies \sf Retardation \: Force = 1500 \times 2$

$\pink{:\implies\underline{\boxed{\sf Retardation \: Force = 3000 N}}}$

$\therefore\:\underline{\textsf{Retardation Force is \textbf{3000 N}}}.$

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