Velectric dipole moment of cuso4 molecule is 3.2 × 10–32 cm. find the separation between copper and sulphate ions.
Answers
Answered by
1
Dipole moment P = qxl
where, Q is magnitude of charge on one particle of dipole which is 2e in case of Cu+2 so distance between them is given by l= P/2e
where ,e is charge on electron = 1.6 *10^-19C
so ,distance is 10^-13 m.
where, Q is magnitude of charge on one particle of dipole which is 2e in case of Cu+2 so distance between them is given by l= P/2e
where ,e is charge on electron = 1.6 *10^-19C
so ,distance is 10^-13 m.
Similar questions