Question

veli.
Prove that:
(1+ tan A-SecA ) ×(1+ tan A+ SecA)= 2tanA​

Answer 1

Step-by-step explanation:

L.H.S.=[secA+(tanA−1)]

[secA−(tanA−1)]−2tanA

=sec

2

A−(tanA−1)

2

−2tanA

sec

2

A−tan

2

A−1+2tanA−2tanA

=1−1=0=R.H.S.