Question

Velicity=20m/s, angle projected with horizontal is 45° , acceleration?
​

Answer 1

Answer:

nsnmsmsjsjnsmwmw dndkd e. ejdnw 2nwks e 2 wnsn w w

Answer 2

$\huge\colorbox{pink}{Required\:Answer:-}$

From projectile motion........

R=u2sin2θg——(1)

Here ,,,,,,,, R= horizontal range of a projectile

u = 20m/s = initial velocity of projection

g =9.8m/s² ≈10m/s²= Acceleration due to gravity

θ = 450 = angle of projection

Therefore equation (1) becomes

R=202sin(900)10 [sincesin900=1]

⇒R=20×2010=20×2=40m