Question

velocity after falling throung 40 m​

Answer 1

Answer:

28.01 m/s

Explanation:

the total height is 40m

let total time be t

intial velocity u=0

case 1: what is the velocity when the body at 20m heigh

from the formula

v^2- u^2 = 2*a*s

v^2- 0^2= 2*9.81* 20

v^2- 392.4

v = /393.4

v = 19.809m/s

case2: velocity when the ball hits the ground from

v^2- u^2= 2*a*s

v^2- 0^2= 2*9.81* 40

v^2 = 784.8

v= /784.8

v=28.01 m/s

MAY BE THIS IS ANSWER HELP YOU

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Answer 2

u =0

s = 40

a= 10m/s²

v²-u² =2as

v²-0 = 2×10 ×40

v² = 800

v= √800 = √8 × √100

v= 2√2 ×10

v= 20√2 m/s

a = v-u/t = 20√2 - 0/t

t= 20√2/10

t= 2√2 sec