Question

Velocity at horizontal position in vertical circular motion

Answer 1

Explanation:

It can be determined using, v²=u²-2gl(1-cos∅)

For a vertical circular motion the initial velocity should be $\sqrt{5gl}$.

So from the formula; v²=5gl-2gl(1-cos90°)

v²=5gl-2gl

v²=3gl

v=$\sqrt{3gl}$