Velocity (in m/s) of a particle moving along x-axis varies with time as, v= (10+ 5t -t^2) At time t=0, x=0. Find (a) acceleration of particle at t = 2 s and (b) x-coordinate of particle at t=3s
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a) 1 m/s. b) 82/2 m/s^2
v=dx/dx
A=dv/dx
just sub the value of t in the give equation
than we get the answer
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