Velocity increases from 2 m/s to 3.5 m/s in 2 second when external force is applied on an
object of 5 kg mass. Find external applied force.
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Answer:
Mass of the body, m = 3 kg
Initial speed of the body, u = 2 m/s
Final speed of the body, v = 3.5 m/s
Time, t = 25 s
Using the first equation of motion, the acceleration (a) produced in the body can be calculated as:
v=u+at
a=
t
(v−u)
=
25
(3.5−2)
=0.06m/s
2
As per Newton's second law of motion, force is given as:
F=ma
=3×0.06=0.18N
Since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.
Step-by-step explanation:
limbholavirendrasing:
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