Question

velocity(m/s)
15
The velocity-time graph of a car is shown in the
right side
Answer the following questions.
i) Which part of the graph shows accelerated
motion? Also calculate the acceleration.
ii) Which part of the graph shows retarded
motion? Also calculate the retardation.
iii) Calculate the distance travelled by the body
in first 2 seconds of the journey.
D
2
s
6
time (5)​

Answer 1

Answer:

Explanation:

Given graph is a VELOCITY-TIME graph of an object.

In VT graph:

1. The slope of the line at a particular time gives the acceleration of the object at that time.

2. Area under the graph gives the displacement of the object.

_______________________________

Coming to the questions:

1. Part AB is accelerated motion as the slope of the graph(which gives the acceleration) is positive.

acceleration = slope

So acceleration = 1 m/s^2

2.Part CD is retarded motion as the slope of the graph(which gives the acceleration) is negative.

So acceleration = -1 m/s^2

Thus retardation is 1 m/s^2

3.

distance of the body in first 4 seconds = area under graph from t=0 to t=4s

area under graph from t=0 to t=4s = area of ∆ABE = 1/2 × 4 × 4 = 8m

Thus distance of the body in first 4 seconds is 8m