Question

velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels at this time.

Answer 1

Answer:

acc to second kinematics equation,

s=ut+1/2at^2

u=3m/s

t=1.8s

a=9.3m/s^2

distance s=3×1.8+1/2×9.3×(1.8)^2

=5.4+15.066=20.466

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