Question

velocity of a block of mass 1 kg moving along x axis is given as v=6-2t where t is time in second and v is in m/s the block is moving in positive x direction at time =0 power developed due to net force at t=4 s is

Answer 1

Answer:

The velocity of particle is zero when v=(20-10t)=0.

That it at t=2sec.v=0

From t=0 to t=2 distance travel

S1=

(20)2

2×10

=20m.

Next 5 meter will be covered in 5=

1

2

×10×t2ort=1s.

∴ The particle covers 25 meters distance in 3 sec.

K.E.att=0 is Ki=

1

2

mu2=

1

2

2×(20)2=400J

KE at t=3 is

Kf=

1

2

mv2=

1

2

2×(10)2=100J

Therefore work done by block from t=0 to t=3s is

ΔW=Kf-Ki=100-400=-300J

Explanation:

hope it will helps you ❤❤

Answer 2

I don’t know the answer