Question

Velocity of a body moving with uniform
acceleration of 3 m/s is changed through 30 m/
sin certain time. Average velocity ofbody during
this time is 30 m/s. Distance covered by it during
this time is???​

Answer 1

Answer:

V  

avg

​  

=  

t

D

​  

⇒0.34=  

t

3.06

​  

 

⇒t=  

0.34

3.06

​  

 = 9 sec

We have, v=u+at

v−u=at

0.18=a×9

⇒a=  

9

0.18

​  

=0.02 m/s  

2

Explanation: