Question

velocity of a body moving with uniform acceleration of 3m/sec2 is changed through 30 m/s in certain time. Average velocity of body during this time is 30 m/s.Distance covered by it during this time is

Answer 1

Hey mate!!!!

As avg velocity = total displacement divided by total time taken

So, in question we provided with a=3m/s^2

∆v=v-u=30 {where v is final velocity and u is intial velocity}

and we know that v=u-at

v-u=at

at=30

t=10 sec

And avg velocity =30

30=s/t

S=30t

s=300m

Hope this helps you!!!!

Answer 2

Explanation:

• a=v/t
• t=v/a
• t=3/30=0.3sec

then,

d=v/t

d= 30/0.1

d=300 m

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