Question

Velocity of a body moving with uniform
acceleration of 3m/s is changed through
30m/s in certain time. Average velocity of
body during this time is 30m/s. Distance
covered by it during this time is
1) 300 m 2) 200 m 3) 400 m 4) 250 m








those who are a boy or a girl answer this​

Answer 1

» Velocity of a body moving with uniform

acceleration of 3m/s² is changed through 30m/s in certain time.

Here..

• Acceleration (a) = 3 m/s²

• Change in velocity (v - u) = 30 m/s

__________ [ GIVEN ]

• We have to find the time (t).

_______________________________

We know that..

Acceleration = $\dfrac{Change\:in\: velocity}{Time\:taken}$

Put the known values in above formula

→ 3 = $\dfrac{30}{t}$

→ t = $\dfrac{30}{3}$

→ t = 10 s

_____________________________

» Average velocity of body during this time is 30 m/s.

• Velocity (v) = 30 m/s

• Time (t) = 10 s

____________ [ GIVEN ]

• We have to find the Distance (d).

___________________________

Now;

Velocity = $\dfrac{Distance}{Time}$

Put the known values in above formula

→ 30 = $\dfrac{d}{10}$

→ 30 × 10 = d

→ d = 300 m

_____________________________

Distance (d) = 300 m

Option 1) 300 m

________ [ ANSWER ]

_____________________________

Answer 2

Answer: 300 m

Explanation:

Acceleration = Change in Velocity / Total Time

3 m/s² = (30 m/s) / T

T = 10 seconds

Distance covered during this time

D = Average velocity × Time

= 30 m/s × 10 s

= 300 m