Question

velocity of a body moving with uniform acceleration of 3m/s^2 is changed through 30 m/s in certain time. average velocity of body during this time is 30m/s. distance covered by it during this time is​

Answer 1

Answer:

Explanation:

As avg velocity = total displacement divided by total time taken

So, in question we provided with a=3m/s^2

∆v=v-u=30 {where v is final velocity and u is intial velocity}

and we know that v=u-at

v-u=at

at=30

t=10 sec

And avg velocity =30

30=s/t

S=30t

s=300m