Question

Velocity of a bus moving with 36 km h-
increases to 72 km h' in 20 s. then its
acceleration would be
-2
ms​

Answer 1

Given:-

▪︎Initial velocity(u)=36km/h

=>36×5/18

=>2×5=10m/s

▪︎Final velocity(v)=72km/h

=>72×5/18

=>4×5=20m/s

▪︎Time(t)=20s

To find:-

▪︎Acceleration(a)

Solution:-

We know that-----

=>a= v-u/t

=>a=20-10/20

=>a=10/20

=>a=0.5m/s²

Thus,acceleration of the bus is 0.5m/s².

Answer 2

Answer:

accereration = final velocity - initial velocity / time

initial velocity = 36 km/h = 10 m/s

final velocity = 72 km/h = 20 m/s

time = 20s

acceleration = 20-10/20

= 10/20

= 0.5m/s^2

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