velocity of a car increase for 30 kilometre per hour to 45km/h in 5 minute acceleration to be uniform,calculate the
distance travelled
Answers
Answer:
Distance travelled = 3.125 km
Step by step explanations :
given that,
velocity of a car increase for 30 kilometre per hour to 45km/h in 5 minute
here,
initial velocity of the car = 30 km/h
it accelerated uniformly and
gives the
final velocity of the car = 45 km/h
time taken by the car to accelerate uniformly = 5 minutes
changing 5 minutes to hour
= 5/60 h
= 1/12 h
now,
we have,
initial velocity(u) = 30 km/h
final velocity(v) = 45 km/h
time taken(t) = 1/12 h
so,
by the equation of motion,
v = u + at
where,
a is acceleration produced in the car
putting the values,
45 = 30 + a(1/12)
a/12 = 45 - 30
a/12 = 15
a = 180 km/h²
now ,
we have,
initial velocity(u) = 30 km/h
final velocity(v) = 45 km/h
acceleration(a) = 180 km/h²
by the equation of motion,
v² = u² + 2as
where,
S is distance travelled during acceleration
putting the values,
(45)² = (30)² + 2(180)s
360s + 900 = 2025
360s = 2025 - 900
360s = 1125
S = 1125/360
= 3.125 km
so,
Distance travelled = 3.125 km
Answer:
Distance travelled = 3.125 km
Step by step explanations:
given,
initial velocity of a car = 30 km/h
final velocity of car = 45 km/h
time taken = 5 minutes
= 5/60 h
= 1/12 h
now,
v = u + at
45 = 30 + a(1/12)
a/12 = 45 - 30
a/12 = 15
a = 180 km/h²
so,
acceleration(a) = 180 km/h²
v² = u² + 2as
S = distance travelled
45² = 30² + 2(180)s
360s = 45² -30²
360s = 2025 - 900
S = 1125/360
= 3.125 km
so,