Question

Velocity of a particle depends upon its displacement as v=
$\sqrt{9 - 6s}$
Distance covered by it in first 4 seconds is?​

Answer 1

Answer:

here is your answer mate...

Step-by-step explanation:

Squaring the given equation, we get

v2=4+4s

Now, comparing it with v2+u2+2as, we get

u=2m/s and a=2m/s2

∴ Displacement at t=2s is

s=ut+12at2 or s=(2)(2)+12(2)(2)2 or s=8cm

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