velocity of a particle increases from 10 m/s to 15 m/s after travelling a distance of 5 metre. its accleration is
Answers
Answered by
4
Answer:
The total distance travelled is
=
625
m
The initial velocity is
u=0ms−1
The acceleration is a=
10ms−2
The time is t=5s
Apply the equation of motion
v=u+at
The velocity is
v=0+10⋅5=50ms−1
The distance travelled in the first
5s is
s=ut+12at2
=0⋅5+12⋅10⋅52=125m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
⋅
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
Answered by
3
Answer: the answer is 625 metre
Explanation:
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