Question

Velocity of a particle increases from 10 m/s to 15 m/s after travelling a distance of 5 m. Its acceleration will be

0.125 m / s^2
12.5 m / s^2
1.25 m / s^2
125.5 m / s^2

Answer 1

Answer :

• Acceleration is 1.25 m/s

Explanation :

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 15 m/s
• Distance (s) = 5 m

Use 3rd equation of motion :

$\longrightarrow \sf{v^2 \: - \: u^2 \: = \: 2as} \\ \\ \longrightarrow \sf{15^2 \: - \: 10^2 \: = \: 2 \: \times \: 5 \: \times \: a} \\ \\ \longrightarrow \sf{225 \: - \: 100 \: = \: 10a} \\ \\ \longrightarrow \sf{10a \: = \: 125} \\ \\ \longrightarrow \sf{a \: = \: \dfrac{125}{10}} \\ \\ \longrightarrow \sf{a \: = \: 1.25} \\ \\ \underline{\underline{\sf{Acceleration \: is \: (c) \: 1.25 \: ms^{-2}}}}$

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Important Points to Remember :

• Acceleration is defined as Rate of change of velocity.

• It is a vector quantity.

• It is denoted by “a”

• SI unit is m/s²

Answer 2

Answer;1.25m/s^2


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