Physics, asked by x613747, 9 months ago

Velocity of a particle increases from 10 m/s to 15 m/s after travelling a distance of 5 m. Its acceleration will be

0.125 m / s^2
12.5 m / s^2
1.25 m / s^2
125.5 m / s^2

Answers

Answered by Anonymous
15

Answer :

  • Acceleration is 1.25 m/s

Explanation :

  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 15 m/s
  • Distance (s) = 5 m

Use 3rd equation of motion :

\longrightarrow \sf{v^2 \: - \: u^2 \: = \: 2as} \\ \\ \longrightarrow \sf{15^2 \: - \: 10^2 \: = \: 2 \: \times \: 5 \: \times \: a} \\ \\ \longrightarrow \sf{225 \: - \: 100 \: = \: 10a} \\ \\ \longrightarrow \sf{10a \: = \: 125} \\ \\ \longrightarrow \sf{a \: = \: \dfrac{125}{10}} \\ \\ \longrightarrow \sf{a \: = \: 1.25} \\ \\ \underline{\underline{\sf{Acceleration \: is \: (c) \: 1.25 \: ms^{-2}}}}

_____________________

Important Points to Remember :

  • Acceleration is defined as Rate of change of velocity.

  • It is a vector quantity.

  • It is denoted by “a”

  • SI unit is m/s²
Answered by charitheswarareddy
3
Answer;1.25m/s^2


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