Question

Velocity of a particle is given by v = (3t^2 + 2t) . Find its average velocity between t = 0 to
t = 3s and also find its acceleration at t = 3s. Motion of the particle is in one dimension.
(A) 11 m/s, 10m/s^2
(B) 12m/s, 20m/s^2
(C) 11m/s, 20m/s^2
(D) None of the given​

Answer 1

Answer:

Explanation:

When t=0

3(0)^2+2(0)=0

when t=3

3(3)^2+2(3)=27+6=33

acceleration=vf-vi/t

=33-0/3

=11m/s

Answer 2

Answer:

which is the CORRECT option please say