Question

Velocity of a particle moving in a straight line varies with its displacement as v=root 4+4s m/s find its displacement in first 2s of its motion

Answer 1

Explanation:

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Answer 2

Given ;-

$v = \sqrt{4 + 4s}$

$= 2 \sqrt{1 + s}$

Applying irrigation on both side.

Applying irrigation on both side.we, get

$|\times \frac{s}{0} \frac{ds}{ \sqrt{1 + s} } = | \times \frac{2}{0} 2dt$

$\frac{ \sqrt{1 + s} }{frac{1}{2} } = 2 |t|$

$\sqrt{1 + s} = 2$

$1 + s = 4$

$s = 3m$

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