Question

velocity of a particle moving in a straight line varies with its displacement as be equal to under rule 4 + 4 S M per second displacement of particle at equal to zero is equal to zero displacement of particle at 2 seconds

Answer 1

It's a differential equation.

v = (4+4s)^0.5

v =ds/dt

ds/dt = (4+ 4s)^0.5

ds/(4+4s)^0.5 = dt

Integrating both sides we get,

0.5*(4+4s)^0.5 + C = t

at t=0, s=0. so we get

C = -1

therefore, at t = 2s we get

s = (t+1)^2 - 1 = 8m