Question

velocity of a particle of mass 1 kg moving rectilinearly is given by v is equal to 25 - 2T + T^2 find the average power of the force acting on the particle between time interval t = 0 t equals to 1 second

Answer 1

velocity of the object is given by equation

$v = 25 - 2t + t^2$

now

velocity at t = 0

$v_i = 25 m/s$

velocity at t = 1

$v_f = 24 m/s$

now work done by all forces is given by

$W = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

$W = \frac{1}{2}*1*(24^2 - 25^2)$

$W = -24.5 J$

now power is given by

$P = \frac{W}{t}$

here t = 1 s

$P = \frac{-24.5}{1}$

P = -24.5 Watt

Answer 2

Answer:

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