Physics, asked by ashishthakre, 11 months ago

velocity of a particle starting from rest varies with position according to equation v=√ax . what is the distance travelled by particle in t second from start?​

Answers

Answered by prashantsinghtiwari
8

Answer:

X/2

Explanation:

apply v^2=u^2+2as 3rd law of motion

here U=0 initially

&v^2=ax

now put ax=0+2as

so S=X/2

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