Physics, asked by bhavananagavalli, 1 month ago

Velocity of a particle varies with time as V = (5 + 2t) ms-1 then its acceleration (A) constant and equal to 5 ms 2 --2 (B) constant and equal to 2 ms (C) zero (D) varies with time as (5t + 2+2) a

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Answered by sarthakshejul

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Answer:

it is correct answer please if you doing this no

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