Question

Velocity of a projectile is 10 m / s . At what angle to the horizontal should it be projected ? So that it covers maximum horizontal distance

Answer 1

it need to project at 45degree.
proof:
$h = \frac{ {u}^{2} { sin }^{2} \alpha }{2g}$
$when \: we \: substitute \: \alpha \: in \: the \: equation \: the \: result \: will \: be \: greater$