Question

velocity of a train changes from 20 m per second to 25 m per second when it accelerates @ 2 m per second square find the distance covered by the train

Answer 1

use the formula V^2=U^2-2as
here V=25,U=20 and a=2
by substituting, we get
25*25=20*20+2*2*s
625-400=4s
225/4=s
hence the distance covered is 225/4

Answer 2

Answer:

Distance, d = 56.25 m

Explanation:

It is given that,

Initial velocity of train, u = 20 m/s

Final velocity of train, v = 25 m/s

Acceleration of the train, a = 2 m/s²

We have to find the distance covered by the train. It can be calculated using third equation of motion. It is given as :

$v^2=u^2+2ax$

x is the distance covered by the train.

$x=\dfrac{v^2-u^2}{2a}$

$x=\dfrac{25^2-20^2}{2\times 2}$

x = 56.25 m

Hence, the distance covered by the train is 56.25 m