Question

velocity of a train changes from 20 m per second to 25 m per second when it accelerator at a rate of 2 m/ s Sq, find distance

Answer 1

t = v-u/a
  = 2.5s

S= 20* 2.5 + 1/2 2* 12.5
  = 5 + 12.5
  = 17.5 m

Answer 2

u=20m v=25m a=2m/s sq
We have to find "s",that is,distance.
So we will use the formula= v^2-u^2=2as
525-400=2*2*s
125=4s
31.25=s