Question

velocity of a train changes from 20 metre per second to 25 metre per second when it accelerates at the rate of 2 metre per second find the distance covered by the train​

Answer 1

$u = 20m {s}^{ - 1} \\ v = 25m {s}^{ - 1} \\ a = 2m {s}^{ - 2} \\ so \\ {v}^{2} - {u}^{2} = 2as \\ \\ (25) {}^{2} - (20) {}^{2} = 2 \times 2 \times s \\ 625 - 400 = 4s \\ \frac{225}{4} = s \\ so \\ s = 56.25m$

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Answer 2

Answer:

Distance, d = 56.25 m

Explanation:

It is given that,

Initial velocity of train, u = 20 m/s

Final velocity of train, v = 25 m/s

Acceleration of the train, a = 2 m/s²

We have to find the distance covered by the train. It can be calculated using third equation of motion. It is given as :
${v}^{2} = {u}^{2} + 2ax$
where x is the distance covered by the train.
$x = \frac{ {v}^{2} - {u}^{2} }{2a}$
$x = \frac{ {25}^{2} - {20}^{2} }{2 \times 2}$
x= 625-400/4
x= 225/4
x = 56.25 m
Hence, the distance covered by the train is 56.25 m