Question

Velocity of a train changes from 20m/s to 25 m/s when it accelerates at a rate
of 2m/s^2. Find the distance covered by the train.​

Answer 1

Here, initial velocity (u)=20m/s

final velocity (v)=25m/s

acceleration (a)=2m/s²

distance (s)=?

By using Newton's third equation of motion , we get:

v²-u²=2as

25×25-20×20=2×2×s

625-400=4s

225=4s

225/4=s

56.25=s

or s= 56.25m

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