Question

Velocity of a train changes from 20m/s to 25m/s . Find the acceleration when the time is 5 second

Answer 1

Initial velocity, u = 20 m/s

Final velocity, v = 25 m/s

Time taken, t = 5 s

We know,

==> v = u + at

Substituting values of the required variables, we get

==> 25 = 20 + 5a

==> 5a = 25 - 20

==> 5a = 5

==> a = 1

Hence, The acceleration of train is 1 m/s²

Answer 2

ANSWER:

Use the formula V^2=U^2-2as

here V=25,U=20 and a=2

by substituting, we get

25*25=20*20+2*2*s

625-400=4s

225/4=s

hence the distance covered is 225/4

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