Question

Velocity of a train changes from 20m/s to 25m/s,when it accelerates at a rate of 2m/s^2. find the distance covered by the train.

Answer 1

the distance covered is 56.25m

Answer 2

Answer : The distance covered by the train is 56.25 m

Explanation :

Initial velocity of the train, u = 20 m/s

Final velocity of the train, v = 25 m/s

Acceleration of the train, $a=2\ m/s^2$

Using third equation of motion :

$v^2-u^2=2as$

$(25\ m/s)^2-(20\ m/s)^2=2\times 2\ m/s^2\times s$

s is the distance covered by the train.

$s=56.25\ m$

Hence, this is the required solution.