Velocity of a train changes from 20m/s to 25m/s when it accelerates at a rate 2m/s2 .find the distance covered by train
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hey buddy here is your answer
by Udit
using third law of motion
v =25 m/s
a =2m/s^2
u=20 m/s
s=?
(25)^2-(20)^2=2×2×s
s=(625-400)/4
s=125/4 =31.25m
by Udit
using third law of motion
v =25 m/s
a =2m/s^2
u=20 m/s
s=?
(25)^2-(20)^2=2×2×s
s=(625-400)/4
s=125/4 =31.25m
atcindia1999:
Thanks bro udit
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