Question

Velocity of a train changes from 20m/s to 25m/s, when it accelerate at a rate 2 m/s2. Find the distance covered by the train.​

Answer 1

Here , initial velocity (u)=20m/s

final velocity (v)=25m/s

acceleration (a)=2m/s2

distance (s)=?

So by using Newton's third law of motion , we get:

v2-u2=2as

25×25-20×20=2×2×s

625-400=4s

225=4s

225/4=s

56.25=s

or s=56.25m

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