Question

Velocity of a train changes from 20ms -1 to 25 ms-1, when it accelerates at a rate
of 2ms-2. Find the distance covered by the train.​

Answer 1

Answer:

55m

Explanation:

a=v-u/t

t=v-u/a

substituting the values,

25-20/2= 2.5 s

Distance travelled=ut+ 1/2*at^2

20*2.5+1/2*2*(2.5)^2

=50+5 m

=55 m

Answer 2

Answer:

u = 20m/s

v = 25m/s

a = 2m/s^2

s = ?

●using 1st equation of motion ,

• v = u +at
• 25 = 20 +(2×t)
• 5 / 2 = t
• t = 2.5 sec

●Using 2nd equation of motion,

• s = ut +1/2at^2
• s = (20× 2.5 ) + 1/2 × 2×2.5×2.5
• s = 50 +6.25
• s = 56.25 m

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