Question

velocity of a train changes from 20ms to 25 ms,when it accelerates at a rate of 2ms -2. Find the distance covered by the train.​

Answer 1

Answer:

using, v2 -u2 = 2as we get

Explanation:

u= initial velocity 20 m/s

v= final velocity 25m/s

Acceleration is 2m/s^2

s =distance ?

v2 - u2 = 2as we have,

(25)2 - (20)2 = 2×2×s

4s = 225

=)s =56.25 m

●Distance covered by the train is 56.25m