velocity of a train increases to 60 km/h from 45km/h in 10 minutes.Find the acceleration in the train
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Hope the answer attached would help
Explanation:
the quantities are solved using SI units.
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sorry the answer would be +25m/s i mistakenly took the initial velocity as final velocity
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Initial velocity (u) = 45 km/h
Final velocity (v) = 60 km/h
Time taken to change the velocity (t) = 10 minutes = 1/6 hour
We know,
a = (v - u)/t
- a = Acceleration,
- v = Final velocity,
- u = Initial velocity and
- t = Time taken.
Hence,
a = (60 km/h - 45 km/h)/(1/6 h)
⟹ a = (15 km/h)/(1/6 h)
⟹ a = (15 km/h × 6)/h
⟹ a = 90 km/h² (Solution)
To convert the acceleration into (m/s²), convert the velocities into (m/s) and the time taken in (s). Then, put the values according to the formula.
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